If the sink temperature is decreased and the source temperature is held constant, then the efficiency of a Carnot engine can be:
A
increased
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B
decreased
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C
remain constant
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D
None of these
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Solution
The correct option is A increased The efficiency of a Carnot engine is given by η=1−TsinkTsource. If Tsink is decreased and Tsource is kept constant we notice that η increases.