Question

If the slop of one of the lines represented by $a{x}^2-6xy+y^2=0$ is the square of the other,then the value of a is

• A. $-27$ or $8$
• B. $-3$ or $2$
• C. $-64$ or $27$
• D. $-4$ or $3$

Answer 1

The correct option is A $-27$ or $8$

$m+m^2=6$
$m^3=a$
$m^3+m^6+3.m^3.6=6^3$
$a^2+19a-216=0$
$a=-27$ or $8$