Question

If the slope of a line passing through the point $A(3,2)$ is $\frac{3}{4}$, then find points on the line which are $5$ units away from the point A.

Answer 1

Point is given by $(3\pm 5\cos \theta ,2\pm 5\sin \theta )$

where, $\tan \theta =slope=\frac{3}{4}$

$⟹\sin \theta =\frac{3}{5}$ and $\cos \theta =\frac{4}{5}$

Hence, $A=(3\pm 4,2\pm 3)$

Hence $A=(7,5)$ or $(-1,-1)$