If the slope of one of the lines represented by $4 a x^{2} + x y + 4 y^{2} = 0$ is the square of the other then a equals :

$\frac{1}{8}$

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$\frac{1}{4}$

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$- \frac{1}{4}$

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$- \frac{1}{8}$

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Solution

The correct option is D
$- \frac{1}{8}$

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If the slope of one of the lines represented by 4ax2+xy+4y2=0 is the square of the other then a equals :

The correct option is D −18

If the slope of one of the lines represented by $4 a x^{2} + x y + 4 y^{2} = 0$ is the square of the other then a equals :

The correct option is D
$- \frac{1}{8}$