If the slope of the curve y=axb−xat the point (1, 1) is 2 then values of a and b respectively
A
1, -2
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B
-1, 2
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C
1, 2
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D
2,7
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Solution
The correct option is C
1, 2
We have, y=axb−x ⇒=dydx=(b−x)a−ax(−1)(b−x2)=ab(b−x)2 ∴[dydx](1,1)=ab(b−1)2(given)....(1)
Since the curve passes through the point (1,1), therefore, 1=ab−1⇒a=b−1
On putting a=b-1 in equation (1), we get (b−1)b(b−1)2=2⇒b=2.∴1=2−1=1.
Hence a =1, b=2
Hence (c) is the correct answer.