Question

If the slope of the line joining points (x, $-$2) and (8, $-$11 ) is $\frac{-3}{4}$ . Find the value of x.

Answer 1

Given: The slope of the line joining points (x, $-$2) and (8, $-$11 ) is $\frac{-3}{4}$.

We know that slope of a line = $\frac{y_2-y_1}{x_2-x_1}=\frac{y_1-y_2}{x_1-x_2}$

$$\begin{gathered} \mathrm{Then}\frac{-11-(-2)}{8-x}=\frac{-3}{4} \\ \Rightarrow \frac{-11+2}{8-x}=\frac{-3}{4} \\ \Rightarrow \frac{-9}{8-x}=\frac{-3}{4} \\ \Rightarrow -3(8-x)=-36 \\ \Rightarrow -24+3x=-36 \\ \Rightarrow 3x=-36+24 \\ \Rightarrow x=\frac{-12}{3}=-4 \end{gathered}$$