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Question

If the solubility of a gas in water at 0C and 1 atm is 1.5 g/L, then calculate the solubility of the same gas in water at 0C and a pressure of 2 atm.

A
3 g/L
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B
0.75 g/L
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C
1.5 g/L
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D
Cannot be determined by the given data.
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Solution

The correct option is A 3 g/L
The solubility of gas is proportional to the pressure of the gas above the liquid.
P1=1 atmSolubility,S1=1.5 g/LP2=2 atmS2=?

From Henry's law,
Pgas=KHXgas
where, Xgas=mole fraction of gas in liquid
Pgas is the partial pressure of gas over liquid surface
KH is constant at same temperature
So,
Solubilitypressure

S1S2=P1P21.5 g/LS2=12
S2(solubility at 2 atm) =21×1.5
=3 g/L

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