If the solubility of $A g_{2} C r O_{4}$ is $S$ mole/lit. Then its solubility product is:

S^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

S^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 S^{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 S^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $4 S^{3}$
$A g_{2} C r O_{4} (s) \Leftrightarrow 2 A g^{+} + C r O_{4}^{2 -}$
$2 S$ $S$

$K_{s p} = [A g^{+}]^{2} \times [C r O_{4}^{2 -}]$

$K_{s p} = (2 S)^{2} \times S = 4 S^{3}$

Hence, option C is correct.

Suggest Corrections

Similar questions

H g_{2} C l_{2}

S

A g_{2} C r O_{4}

25^{\circ} C

8.0 \times 10^{- 5}

{A g}_{2} C r O_{4}

s

^{- 1}

2.5 \times 10^{- 9}

m o l e s^{2} / l i t^{2}

25^{\circ} C

x

Join BYJU'S Learning Program