Question

If the solubility of any gas in the liquid at $1$ bar pressure is $0.05$ mol/L. What will be its solubility at $3$ bar pressure, keeping the temperature constant?

• A. $\frac{0.05}{3}$ mol/L
• B. $0.15$ mol/L
• C. $0.05$ mol/L
• D. $1.0$ mol/L

Answer 1

The correct option is B $0.15$ mol/L

P = K${}_H$C. where

P = partial pressure

c= conc. of the solute

and K${}_H$= henry's law constant

now, $\frac{p_1}{p_2}=\frac{B_1}{B_2}$

$\frac{1}{3}=\frac{0.05}{B_2}$

$B_2=0.05\times 3=0.15$ mol/L.

Hence, the correct option is $\text{B}$