Question

If the solubility product of $Pb{I}_2$ is $3.2\times {10}^{-8}$, its solubility will be

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

$Pb{I}_2\to P{b}^{2+}+2I^{-}$
$K_{sp}=s\times (2s{)}^2=4s^{3}3.2\times {10}^{-18}\to 3.2\times {10}^{-8}{s}^3=0.8\times {10}^{-8}=8\times {10}^{-9}s=\sqrt[3]{38\times {10}^{-9}}s=2\times {10}^3$