Question

If the solution of the $Cu{SO}_4$ in which copper rod is immersed in diluted to 10 times, the oxidation electrode potential:

• A. increase by $0.030$ volt
• B. decrease by $0.30$ volt
• C. increase by $0.059$ volt
• D. decrease by $0.0059$ volt

Answer 1

The correct option is A increase by $0.030$ volt

If the solution is diluted to 10 times, the molar concentrations of $C{u}^{2+}$reduced to one-tenth of its original value.

The Nernst equation for the following reaction can be calculated as

$C{u}^{2+}+2e^{-1}\to Cu$

$E=E^0+\frac{0.059}{2}log{Cu}^{2+}$

by decreasing the concentration,${Cu}^{2+}$ by $\frac{1}{10}$

then, E will be decreased $\frac{0.059}{2}$=0.030V

Hence the correct option is A.