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Question

If the solution set of |2x1|+|3x4|=|5x5| is x(,p ][43,), then the value of p is

A
1
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B
12
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C
2
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D
0
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Solution

The correct option is B 12
|2x1|+|3x4|=|5x5|
Here 5x5=(2x1)+(3x4)
So,
(2x1)(3x4)0
(|x+y|=|x|+|y|, then xy0)
(x12)(x43)0x(,12][43,)
Hence the value of p is 12

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