Question

If the solutions of the equation $x^2+3x-18=0$ are -6, 3, then the roots of the equation $2(x^2+3x-18)=0$ are _____.

• A. -6, 6
• B. -12, 6
• C. -6, 3
• D. 3, 3

Answer 1

The correct option is C -6, 3

The roots of a quadratic equation do not change when it is multiplied by a constant non-zero real number.

So when the equation $x^2+3x-18=0$ is multiplied by 2, the roots still remain the same i.e. -6 and 3.