If the solutions of the equation $x^{2} + 3 x - 18 = 0$ are -6, 3 then the roots of the equation $2 (x^{2} + 3 x - 18) = 0$ are

-6, 6

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-12, 6

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-6, 3

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3, 3

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Solution

The correct option is C
-6, 3

The roots of a quadratic equation do not change when it is multiplied by a constant non-zero real number. So when the equation $x^{2} + 3 x - 18 = 0$ is multiplied by 2, the roots still remain the same i.e. -6, 3

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Similar questions

If the roots of the equation, $x^{2} + 3 x - 18 = 0$ are $- 6, 3$ then the roots of the equation $2 (x^{2} + 3 x - 18) = 0$ are

x^{2} + 3 x - 18 = 0

- 6, 3

2 (x^{2} + 3 x - 18) = 0

x^{2} + 3 x - 18 = 0

2 (x^{2} + 3 x - 18) = 0

x^{2} + 3 x - 18 = 0

2 (x^{2} + 3 x - 18) = 0

α, β

2 x^{2} + 3 x + 1 = 0

\frac{1}{α}, \frac{1}{β}

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