If the specific heat of lead is $0.03 c a l g^{- 1}^{o} C^{- 1}$ , thermal capacity of 500 g of lead is

5 c a l^{o} C^{- 1}

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10 c a l^{o} C^{- 1}

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15 c a l^{o} C^{- 1}

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20 c a l^{o} C^{- 1}

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Solution

The correct option is C $15 c a l^{o} C^{- 1}$
Given $S = 0.03 c a l g^{- 1}^{o} C^{- 1}$
$m = 500 g$
$∴ C = m S = 500 \times 0.03 = 15 c a l^{o} C^{- 1}$

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