Question

If the specific heat of lead is $0.03cal{g}^{-1}{}^o{C}^{-1}$, thermal capacity of 500 g of lead is

• A. $5cal{}^o{C}^{-1}$
• B. $10cal{}^o{C}^{-1}$
• C. $15cal{}^o{C}^{-1}$
• D. $20cal{}^o{C}^{-1}$

Answer 1

The correct option is C $15cal{}^o{C}^{-1}$

Given $S=0.03cal{g}^{-1}{}^o{C}^{-1}$
$m=500g$
$\therefore C=mS=500\times 0.03=15cal{}^o{C}^{-1}$