If the speed and radius both are trippled for a body moving on a circular path, then the new centripetal force will be:

F_{2} = 2 F_{1}

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F_{2} = F_{1}

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F_{2} = 3 F_{1}

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F_{2} = F / 3

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Solution

The correct option is C $F_{2} = 3 F_{1}$
Initial centripetal force $F_{1} = \frac{m v_{1}^{2}}{r_{1}}$
But the speed and radius are changed as $v_{2} = 3 v_{1}$ and $r_{2} = 3 r_{1}$ respectively.
$∴$ New centripetal force $F_{2} = \frac{m v_{2}^{2}}{r_{2}} = \frac{m (3 v_{1})^{2}}{3 r_{1}} = 3 F_{1}$

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If the speed and radius both are trippled for a body moving on a circular path, then the new centripetal force will be:

The correct option is C F2=3F1Initial centripetal force F1=mv21r1But the speed and radius are changed as v2=3v1 and r2=3r1 respectively.∴ New centripetal force F2=mv22r2=m(3v1)23r1=3F1