If the speed of a car is given as v=3t2+2t+3m/s, total distance covered by the car in 10sec is
A
1230m
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B
1030m
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C
930m
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D
1130m
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Solution
The correct option is D1130m Given, the speed of the car is v(t)=3t2+2t+3
and, distance S=∫t0v(t)dt ⇒S=∫100(3t2+2t+3)dt=[t3+t2+3t]100 ⇒S=(103+102+3×10)−(0)=1130m