The correct option is A 60 m/s,36 m/s
Given, speed of the particle as v(t)=6t2+2t
So, the speed of the particle at t=3 sec, is given as
v(t=3 sec)=6×32+2×3=60 m/s
Now, average speed of the car is given by
Total distance covered (S)Total time taken (t)
Given, the speed of the car is v(t)=6t2+2t
and, distance =∫t0v(t)dt
⇒ S=∫40(6t2+2t)dt=[2t3+t2]40
⇒ S=(2×43+42)−(0+0)=144 m
Thus, average speed of the car is 1444=36 m/s