If the speed of an aeroplane is reduced by 40km/hr, it takes 20 minutes more to cover 1200km, then the speed of the aeroplane is .
A
360 km/hr
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B
380 km/hr
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C
400 km/hr
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Solution
The correct option is C 400 km/hr Let the speed of the aeroplane be x km/hr
Time = DistanceSpeed ∴ Time taken to cover 1200km = 1200x
Reduced speed = x−40 km/hr ∴ Time taken to cover 1200km in reduced speed = 1200x−40
Given: 1200x−40 - 1200x=13 [ 20 minutes = 13 hours] ⇒48000x(x−40)=13 ⇒144000=x2−40x ⇒x2−40x−144000=0 ⇒x2−400x+360x−144000=0 ⇒x(x−400)+360(x−400)=0 ⇒(x+360)(x−400)=0 ⇒x=−360orx=400
Since speed cannot be negative, we get x = 400 km/hr