If the speed of an aeroplane is reduced by 40km/hr, it takes 20 minutes more to cover 1200km. Find the speed of the aeroplane.
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Let the speed of the aeroplane be x km/hr
Time = DistanceSpeed
∴ Time taken to cover 1200km = 1200x
Reduced speed = x−40 km/hr
∴ Time taken to cover 1200km in reduced speed = 1200x−40
Given:
1200x−40 - 1200x = 13 [ 20 minutes = 13 hours]
⇒ 48000x(x−40) = 13
⇒ 144000=x2−40x
⇒ x2−40x−144000=0
⇒ x2−400x+360x−144000=0
⇒ x(x−400)+360(x−400)=0
⇒ (x+360)(x−400)=0
⇒ x=−360 or x=400
Since speed cannot be negative, we get x = 400 km/hr