If the speed of light is 3-0 - 108 m s -1- calculate the distance covered by light in 2-00 ns-

According to the question: Time taken to cover the distance = 2.00 ns = 2.00 times; 10 ndash;9 s Speed of light = 3.0 times; 108 ms ...

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Standard VI

Physics

Rectilinear Propagation of Light

If the speed ...

Question

If the speed of light is 3.0 ×10⁸ m s^-1, calculate the distance covered by light in 2.00 ns.

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Solution

According to the question:
Time taken to cover the distance = 2.00 ns
= 2.00 × 10^–9 s
Speed of light = 3.0 × 10⁸ ms^–1
Distance travelled by light in 2.00 ns
= Speed of light × Time taken
= (3.0 × 10⁸ ms ^–1) (2.00 ×10^–9 s)
= 6.00 × 10^–1 m
= 0.600 m

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If the speed of light is 3.0 ×108 m s-1, calculate the distance covered by light in 2.00 ns.

According to the question:Time taken to cover the distance = 2.00 ns = 2.00 × 10–9 sSpeed of light = 3.0 × 108 ms–1Distance travelled by light in 2.00 ns= Speed of light × Time taken= (3.0 × 108 ms –1) (2.00 ×10–9 s)= 6.00 × 10–1 m= 0.600 m

If the speed of light is 3.0 ×10⁸ m s^-1, calculate the distance covered by light in 2.00 ns.

According to the question:
Time taken to cover the distance = 2.00 ns
= 2.00 × 10^–9 s
Speed of light = 3.0 × 10⁸ ms^–1
Distance travelled by light in 2.00 ns
= Speed of light × Time taken
= (3.0 × 10⁸ ms ^–1) (2.00 ×10^–9 s)
= 6.00 × 10^–1 m
= 0.600 m