Question

If the speed of light is $3.0\times {10}^8$m $s^{-1}$, calculate the distance covered by light in $2.00$ ns.

• A. 0.6 m
• B. 0. 3 m
• C. 0.9 m
• D. 1.2 m

Answer 1

Answer: (A)

0.6 m

1 ns = ${10}^{-9}$ second

and light travels $3\times {10}^8$ meter in one second

so in ${10}^{-}9$ second light travels $3\times {10}^8\times {10}^{-9}$m

similarly in 2 ns = $3\times {10}^8\times {10}^{-9}\times 2=0.6$ m