Question

If the speed of light Is $3\times {10}^8\raisebox{1ex}{$m$}\!\left/ \!\raisebox{-1ex}{$s$}\right.$, Calculate the distance covered by light in $2.00ns$.

Answer 1

Step 1: Given data

Speed of light $\left(v\right)$= $3\times {10}^8\raisebox{1ex}{$m$}\!\left/ \!\raisebox{-1ex}{$s$}\right.$

Time $\left(t\right)$ = $2.00ns=2\times {10}^{-9}s$

Step 2: Formula used

Distance covered $\left(S\right)$ = speed of light $\left(v\right)$ x time$\left(t\right)$

Step 3: Calculation

Hence, $$\begin{gathered} S=3\times {10}^8\times 2\times {10}^{-9} \\ =0.6m \end{gathered}$$

Thus, distance covered will be $0.6m$.