Question

If the speed of light is $3.0\times {10}^{8}m{s}^{-1}$, calculate the distance covered by light in 2.00 ns.

Answer 1

Given :

Speed of light $=3\times {10}^{8}m{s}^{-1}$

Times$=2.00nsec=2\times {10}^{-9}s$

As we know,

Distance covered $=Speed\times time$

The distance traveled is the product of speed and time.

Thus, in 2.00 nsec, the light will travel a distance of $3.00\times {10}^8{ms}^{-1}\times 2.00\times {10}^{-9}s=0.600m$