The correct option is A 2t4−t3+2t m,14 m/s
Given, the speed of the particle is v(t)=8t3−3t2+2
So, the distance as a function of time is given as
∫v(t)dt
⇒ S=∫(8t3−3t2+2)dt=2t4−t3+2t m
Thus, the distance travelled in 2 sec is S=2×24−23+2×2=28 m
Hence, average speed of the particle is
Total distance travelled (S)Total time taken (t)=282=14 m/s