wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If the square root of 35126415+610 = m2k3+5 . Find k+m

Open in App
Solution

It is given that 35126415+610=m2k3+5. Squaring both sides, we get:

(35126415+610)2=(m2k3+5)2

35126415+610=(m2)2+(k3)2+(5)2
+(2×m2×k3)+(2×k3×5)+(2×5×m2)
((a+b+c)2=a2+b2+c2+2ab+2bc+2ca)

35126415+610=2m2+3k2+522mk62k15+2m10

Now, by comparing the coefficients of 6, 10 and 15, we have:

2mk=12mk=122mk=6

2k=4k=42k=2

2m=6m=62m=3

Therefore, k+m=2+3=5

Hence, k+m=5.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Addition of Polynomials
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon