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Question

If the standard deviation of a variable X is σ , then the standard deviation of variable aX+bc is


A

aσ

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B

acσ

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C

|ac|σ

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D

aσ+bc

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Solution

The correct option is C

|ac|σ


Y = \frac{aX+b}{c} \)

¯¯¯¯Y=yin=ax+nbcn

axn+nbnc

a¯¯¯¯Xc+bc

Var (X) =(xi¯¯¯¯X)2n=σ2

Var(Y) =(yi¯¯¯¯Y)2n

=(aXc+bcac×bc)2n

=(aXcac¯¯¯¯X)2n


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