wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If the standard deviation of X is σ, then s.d. of the variable U=aX+bc where a,b,c are constants is

A
caσ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
acσ
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
bcσ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
c2a2σ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B acσ
S.D of X=σ
U=aX+bcXx1,x2,...xnUax1+bc,ax2+bc,...xn+bc
We know that
Var(pX+q)=p2Var(X)
So, Var(U)=Var(aX+bc)=Var(aXc+bc)=(ac)2Var(X)
So, S.D of U=(ac)2Var(X)=acσ

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Measure of Dispersion
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon