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Question

If the standard deviation of X is σ, then s.d. of the variable U=aX+bc where a,b,c are constants is

A
caσ
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B
acσ
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C
bcσ
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D
c2a2σ
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Solution

The correct option is B acσ
S.D of X=σ
U=aX+bcXx1,x2,...xnUax1+bc,ax2+bc,...xn+bc
We know that
Var(pX+q)=p2Var(X)
So, Var(U)=Var(aX+bc)=Var(aXc+bc)=(ac)2Var(X)
So, S.D of U=(ac)2Var(X)=acσ

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