If the straight line is at an angle of $45^{o}$ with $b = 1$ . Calculate frequency if the atomic number of an atom is $50$ .

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Solution

By applying in the equation,
$\sqrt{V} = a z - a b$

$y = m x + c$
$s l o p e = m x$
$\sqrt{v} - a x i s i n t e r c e p t = (- a b)$
$t a n 45^{0} = 1 = a$
$- a b = 1 \Rightarrow b = - 1$
$\sqrt{v} = z + 1$
$\sqrt{v} = 50 + 1$
$v = 50^{2}$
$v = 260 s^{- 1}$

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If the straight line is at an angle of 45o with b=1. Calculate frequency if the atomic number of an atom is 50.

By applying in the equation,√V=az−ab y=mx+cslope=mx√v−axisintercept=(−ab)tan450=1=a−ab=1⇒b=−1√v=z+1√v=50+1v=502v=260s−1

If the straight line is at an angle of $45^{o}$ with $b = 1$ . Calculate frequency if the atomic number of an atom is $50$ .

By applying in the equation,
$\sqrt{V} = a z - a b$

$y = m x + c$
$s l o p e = m x$
$\sqrt{v} - a x i s i n t e r c e p t = (- a b)$
$t a n 45^{0} = 1 = a$
$- a b = 1 \Rightarrow b = - 1$
$\sqrt{v} = z + 1$
$\sqrt{v} = 50 + 1$
$v = 50^{2}$
$v = 260 s^{- 1}$