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Question

If the straight lines x−1k=y−22=z−33 & x−23=y−3k=z−12 intersect at a point, then the value of k equals

A
5
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B
2
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C
2
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D
5
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Solution

The correct option is D 5
The line xx1a1=yy1b1=zz1c1 and xx2a2=yy2b2=zz2c2

intersect if ∣ ∣x2x1y2y1z2z1a1b1c1a2b2c2∣ ∣=0

∣ ∣112k233k2∣ ∣=0

2k2+5k25=0

(2k5)(k+5)=0

k=5,k=52, but k=52 rejected as k is not an integer.

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