If the straight lines y=4−3x , ay=x+10, 2y+bx+9=0 represents three consecutive sides of a rectangle then the value of ab is
y=4−3x is perpendicular with ay=x+10
So, (−3)×1a=−1
⇒a=3
And ay−x−10=0 is also perpendicular with 2y+bx+9=0
So, 1a×−b2=−1
⇒b=2a
⇒b=6
So, value of ab is 3×6=18