If the stress produced in a material is P and strain is S then according to Hooke's law, the modulus of elasticity is

K = \frac{P}{S^{2}}

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K = \frac{S}{P}

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K = P S

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K = \frac{P}{S}

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Solution

The correct option is D $K = \frac{P}{S}$
Modulus of elasticity = $\frac{S t r e s s}{S t r a i n}$

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^{'} K^{'}

^{'} p^{'}

\begin{matrix} C o l u m n - I & C o l u m n - I I (A) (N H_{4})_{2} S O_{4} & (P) h = \sqrt{\frac{K_{H}}{C}} (B) K C l & (Q) p^{H} = \frac{1}{2} [p^{K_{w}} + p^{K_{a}} + l o g c] (C) C H_{3} C O O K & (R) K_{H} = \frac{K_{w}}{K_{b}} (D) (N H_{4})_{2} S & (S) [H^{+}] = [O H^{-}] (t) p^{H} = \frac{1}{2} [P^{K_{w}} + P^{K_{a}} - P^{K_{b}}] \end{matrix}

P \cap Q = K

K

s

\frac{s}{4}

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