Question

If the subsidiary quantum number of a subenergy level is 4, the maximum and minimum values of the spin multiplicities are:

• A. 9, 1
• B. 10, 1
• C. 10, 2
• D. 4, -4

Answer 1

The correct option is B 10, 1

Subsidiary quantum number is also known as azimuthal quantum number.
So, l = 4;
number of degenerate orbitals = $2l+1=9$;
maximum total spins $=9\times \frac{1}{2}$
maximum multiplicity $=2S+1$
$=2\times \frac{9}{2}+1=10$
minimum value will be given when no unpaired $e^{-}$ are present. $S=0$
minimum multiplicity $=2S+1=(2\times 0)+1=1$