If the sum and the product of zeros of a quadratic polynomial $k x^{2} - (k + 1) x + (t - 1)$ are 5 and 6 respectively, find the value of k $\times$ t.

0

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- \frac{1}{8}

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- \frac{1}{3}

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\frac{5}{8}

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Solution

The correct option is D $\frac{5}{8}$

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