If the sum and the product of zeros of a quadratic polynomial $k x^{2} - (k + 1) x + (t - 1)$ is 5 and 6, respectively, find the value of k $\times$ t.

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- \frac{1}{8}

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- \frac{1}{3}

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\frac{5}{8}

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Solution

The correct option is D $\frac{5}{8}$

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Similar questions

If the sum of the zeros of the quadratic polynomial $k x^{2} - 3 x + 5$ is 1, write the value of k.

f (t) = k t^{2} + 2 t + 3 k

If one zero of the quadratic polynomial $k x^{2} + 3 x + k$ is 2 then the value of k is

(a) $\frac{5}{6}$ (b) $\frac{- 5}{6}$ (c) $\frac{6}{5}$ (d) $\frac{- 6}{5}$

If the sum of the zeros of the quadratic polynomial $k x^{2} + 2 x + 3 k$ is equal to the product of its zeros then k = ?

(a) $\frac{1}{3}$ (b) $\frac{- 1}{3}$ (c) $\frac{2}{3}$ (d) $\frac{- 2}{3}$

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