If the sum 1-3 and 1-4 is x times the difference of 1-3 and 1-4- then the value of x is equal to

The correct option is D 7According to the question, #10; #10; 13+14=x( 13 14 #10;) #10; #10; 4+312=x( 4 312) #10; #10; x=7 #10; ...

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Ratio and Proportion

If the sum ...

Question

If the sum $\frac{1}{3}$ and $\frac{1}{4}$ is x times the difference of $\frac{1}{3}$ and $\frac{1}{4}$ , then the value of x is equal to

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x = 1 + \frac{1}{2 \times 1!} + \frac{1}{4 \times 2!} + \frac{1}{8 \times 3!}

y = 1 + \frac{x^{2}}{1!} + \frac{x^{4}}{2!} + \frac{x^{6}}{3!} + . . . . .

{log}_{e} y

x^{4} + \frac{1}{x^{4}} = 119

x > 1

x^{3} - \frac{1}{x^{3}}

3 \frac{1}{x} \times 3 \frac{3}{4} = 12 \frac{1}{2}

x + y = 4

\frac{1}{x} + \frac{1}{y} = 4

x^{3} + y^{3}

\frac{x - 1}{2} = \frac{1 - y}{- a} = \frac{z}{4}

\frac{x - 3}{1} = \frac{2 y - 3}{4} = \frac{z - 2}{2}

a

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