If the sum of a 2-digit number ab and the number obtained by reversing its digits is divided by 11, the remainder is ___.
0
Given: 2-digit number ab
Number obtained by reversing its digits = ba
Expanded form of the 2-digit number ab = 10a + b
Expanded form of the 2-digit number ba = 10b + a
Adding both, we get
(10a + b) + (10b + a)
= 11a + 11b
= 11(a + b) which is divisible by 11
When 11(a + b) is divided by 11, we get (a + b) as quotient and 0 as remainder.