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Question

If the sum of a 2-digit number ab and the number obtained by reversing its digits is divided by 11, the remainder is ___.


A

2

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B

1

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C

0

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D

11

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Solution

The correct option is C

0


Given: 2-digit number ab

Number obtained by reversing its digits = ba

Expanded form of the 2-digit number ab = 10a + b

Expanded form of the 2-digit number ba = 10b + a

Adding both, we get
(10a + b) + (10b + a)
= 11a + 11b
= 11(a + b) which is divisible by 11

When 11(a + b) is divided by 11, we get (a + b) as
quotient and 0 as remainder.


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