Question

If the sum of a 2-digit number ab and the number obtained by reversing its digits is divided by 11, the remainder is ___.

• A. 2
• B. 1
• C. 0
• D. 11

Answer 1

The correct option is C

0

Given: 2-digit number ab

Number obtained by reversing its digits = ba

Expanded form of the 2-digit number ab = 10a + b

Expanded form of the 2-digit number ba = 10b + a

Adding both, we get
(10a + b) + (10b + a)
= 11a + 11b
= 11(a + b) which is divisible by 11

When 11(a + b) is divided by 11, we get (a + b) as quotient and 0 as remainder.