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Question

If the sum of coefficients in the expansion of (1xsinθ+x2)n is P, then

A
minimum value of P=1
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B
minimum value of P=1
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C
maximum value of P=3n
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D
maximum value of P=2n
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Solution

The correct options are
A minimum value of P=1
C maximum value of P=3n
​​​​​​Sum of coefficients in (1xsinθ+x2)n is (1sinθ+1)n
(putting x=1) This sum is greatest when sinθ=1,
Therefore maximum value of sum of coefficient will be 3n
And sum will be minimum when sinθ=1
Therefore minimum value will be 1

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