If the sum of exterior angles of a polygon is one-ninth the sum of its interior angles, then the polygon has
20
Let the number of sides = n
Sum of exterior angles of a polygon = 360∘
Sum of interior angles of n sided polygon =(2n−4)×90∘
Given, sum of exterior angles of a polygon is one-ninth the sum of its interior angles
⇒360=19[(2n−4)×90∘]
⇒ 360 = (2n - 4)×10
⇒36 = 2n - 4
⇒2n = 40
⇒n = 20
∴ The given polygon has 20 sides.