If the sum of exterior angles of a polygon is one - ninth the sum of its interior angles, then the polygon has
20
Let the number of sides = n
Sum of exterior angles = 360∘
Sum of interior angles =(n−2)×180∘
Given,
360=19[(n−2)×180∘]
360 = (n - 2) 20
18 = n - 2
n = 20
Hence (A)