If the sum of first 10 natural numbers is S1 and that of first 10 whole numbers is S2 . Then S1−S2 is
10
The set of natural numbers are (1,2,3,4,5...)
The set of whole numbers are (0,1,2,3...)
Sn=n2[2a+(n−1)d]
where Sn is the sum of n terms of the AP,
'n' is the number of terms,
'a' is the first term,
'd' is the common difference.
S1=n2(2a+(n−1)d)
S1=102(2(1)+(10−1)1)=5(2+9)=55
Similarly,
S2=102[2(0)+(10−1)1]
S2=5((2×0)+9)=45
∴S1−S2=55−45=10