If the sum of first 10 natural numbers is S1 and that of first 10 whole numbers is S2 . Then S1−S2 is
10
The sets of natural and whole numbers are (1,2,3,4,5...) and (0,1,2,3...)
S1=n2(2a+(n−1)d)=5(2+9)=55 and
S2=5((2×0)+9)=45
S1−S2=55−45=10