The correct option is B 2
Let, 'a' be the first term and 'd' be the common difference of the AP.
∵ Sum of n terms of an AP is:
n2×(2a + (n-1)d)
∴ Sum of first 7 terms
= 72×(2a + (7-1)d)
= 72× (2a + 6d)
= 7 × (a+3d)
and Sum of first 17 terms
= 172×(2a + (17-1)d)
= 172× (2a + 16d)
= 17 × (a + 8d)
Given, Sum of first 7 terms = 49 and Sum of first 17 terms = 289
∴ 7 × (a+3d) = 49
⇒ a + 3d = 7 ......(1)
and, 17 × (a + 8d) = 289
⇒ a + 8d = 17.........(2)
Subtracting (1) from (2), we get
5d = 10
⇒ d = 2
∴ Common difference of the given AP is 2.