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Question

If the sum of first 7 terms of an AP is 49 and that of first 17 terms is 289, find the sum of first n terms.

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Solution

Let a be the first term and d be the common difference of the given AP.
Then we have:
Sn = n22a + n-1dS7 = 722a + 6d = 7[a +3d] S17 =1722a + 16d = 17[a +8d]

However, S7 = 49 and S17 = 289
Now, 7[a + 3d] = 49
⇒ a + 3d = 7 ...(i)
Also, 17[a + 8d] = 289
ā€‹⇒ a + 8d = 17 ...(ii)

Subtracting (i) from (ii), we get:
5d = 10
⇒ d = 2

Putting d = 2 in (i), we get:
a + 6 = 7
⇒ a = 1
Thus, a = 1 and d = 2

∴ Sum of n terms of AP = n22×1 + n-1×2 = n [ 1+ (n-1)] = n2

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