If the sum of first n terms of an A.P is given by Sn=5n2+3n, find the nth term of the A.P.
A
10n−2
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B
10n−3
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C
10n−4
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D
10n−6
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Solution
The correct option is A10n−2 Given, Sn=5n2+3n ∴Sn−1=5(n−1)2+3(n−1)=5(n2−2n+1)+3n−3 ⇒Sn−1=5n2−10n+5+3n−3=5n2−7n+2 Now, nth term an=Sn−Sn−1 ⇒an=(5n2+3n)−(5n2−7n+2) ⇒an=10n−2