Question

If the sum of four consecutive integers is $110$, what is the value of the third consecutive integer?

• A. $26$
• B. $27$
• C. $28$
• D. $29$

Answer 1

Answer: (C)

$28$

Let the four consecutive numbers be $x,x+1,x+2$ and $x+3$.
Therefore, $x+x+1+x+2+x+3=110$
$4x+6=110$
$4x=110-6$
$4x=104$ (Divide both sides by $4$)
$x=26$
The third number be $x+2$
So, the third number is $28$.