Question

If the sum of four consecutive integers is $38$, what is the value of the second consecutive integer?

• A. 8
• B. 9
• C. 10
• D. 11

Answer 1

Answer: (B)

9

Let the four consecutive numbers be $x,x+1,x+2$ and $x+3$.
Therefore, $x+x+1+x+2+x+3=38$
$4x+6=38$
$4x=38-6$
$4x=32$ (Divide both sides by $4$)
$x=8$
So, the second number is $9$.